(0.3 + 0.6) * 2 = 1.8 m; The total length of the rods for the rings will be: 74 * 1.8 = 133.2 m; In order to...
Читать дальше(0.3 + 0.6) * 2 = 1.8 m; The total length of the rods for the rings will be: 74 * 1.8 = 133.2 m; In order to...
Читать дальше37 / 0.5 = 74 pcs. In the event that the gap between the rods is 0.3 m, and the height of the lattice is 0.6 m, then...
Читать дальшеNext: 222 + 30 = 252 m. As a result, we get that it takes 252 m reinforcement. Since, in addition to the aforementioned number of rods (ribbed),...
Читать дальшеSuppose that the rod has one connection, then: 6 (the number of rods in the diagram) * 5 (number of walls) = 30 (number of clutches), which means...
Читать дальше30 + 7 = 37m - the length of the base (total); 37 * 6 = 222 m As a result, we get that the necessary length of...
Читать дальшеSuppose that the reinforcement scheme involves the presence of 6 longitudinal rods with a section of 1.2 cm. Then we will get: (7 + 8) * 2 =...
Читать дальшеConsider the example of how to make the correct calculations and set the required number of reinforcement for equipment of the foundation 7 * 8 m, with 7...
Читать дальшеIn order to determine the number of ribbed rods, calculate the perimeter of the structure and add to it the length of the walls (internal, under which the...
Читать дальшеConsider how the required amount of reinforcement for the strip foundation is calculated. And the correct calculation is necessary so that in the future it is not necessary...
Читать дальшеIn order to protect the rod from corrosion, it is buried in the foundation by 50 mm, and the gap between the shared rods is 30 cm. We...
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